Manage 32-bit numbers with 16-bit registers in 8086

Question

I am trying to write a program that receives two six-digit decimal numbers and shows their addition, but in 16 bit 8086 I defined the numbers as a double word and put LO in WORD 1 and HO in word 2. similar to the code below but I have no idea what to do next , can any body offer me an algorithm for the following operations? Thnx

x dd(?)
    next_no:
    mov cl,2
    mov ch,4

two_bit:
getch

sub al,30h
mov bl,10
mul bl
mov di,ax
add word ptr x+2,di

dec cl
jnz two_bit
fourbit:
getch
sub al,30h
mov bl,10
mul bl
mov di,ax
add word ptr x,di
dec ch
jnz fourbit

in this program, di is the place to store the number made through the loop when the user enters the number di will be a multiple of 10, and the new digit will add di like: get 28 di = 0 * 10 + 2 = 2 di = 2 * 10 * + 8 = 28

Answer 1

, , .

, 32- DX: AX 32- CX: BX ( , 16 DX, , 16 AX). DX: AX, :

    add ax,bx
    adc dx,cx

add C () 1 0 , . adc ( ). , , adc.