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Python masking bit

I have a byte (from some other provider) where the potential bit masks look like this:

value1 = 0x01 value2 = 0x02 value3 = 0x03 value4 = 0x04 value5 = 0x05 value6 = 0x06 value7 = 0x40 value8 = 0x80

I can count ONE from value1 through value6. And then the value 7 may or may not be set. value8 may or may not be set.

So this is legal: value2 | value7 | values8 This is not legal: value1 | value3 | value7

I need to find out if the value is set to 7, the value to 8 is set, and what is the remaining value.

I have the following python code. Is there a more elegant way to do this?

value1 = 0x01
value2 = 0x02
value3 = 0x03
value4 = 0x04
value5 = 0x05
value6 = 0x06
value7 = 0x40
value8 = 0x80

def format_byte_as_bits(value):
    return format(value,'b').zfill(8)

def mask_bits_on_byte(byte,mask):
    inverse_of_mask = mask ^ 0b11111111
    return byte & inverse_of_mask

def parse_byte(byte):

    value7_set = byte & value7 == value7
    value8_set = byte & value8 == value8
    byte = mask_bits_on_byte(byte,value7)
    byte = mask_bits_on_byte(byte,value8)
    base_value = byte
    return value7_set,value8_set,base_value

# Example 1
byte = value3 | value7
value7_set,value8_set,base_value = parse_byte(byte)
print("base_value = "+str(base_value))
print("value7_set = "+str(value7_set))
print("value8_set = "+str(value8_set))
print()

# Output:
# base_value = 3
# value7_set = True
# value8_set = False

# Example 2
byte = value5
value7_set,value8_set,base_value = parse_byte(byte)
print("base_value = "+str(base_value))
print("value7_set = "+str(value7_set))
print("value8_set = "+str(value8_set))
print()

# Output:
# base_value = 5
# value7_set = False
# value8_set = False

# Example 3
byte = value1 | value7 | value8
value7_set,value8_set,base_value = parse_byte(byte)
print("base_value = "+str(base_value))
print("value7_set = "+str(value7_set))
print("value8_set = "+str(value8_set))

# Output:
# base_value = 1
# value7_set = True
# value8_set = True

- stackoverflow. , ! , , ! . , , !

EDIT2 - :

value1 = 0x01
value2 = 0x02
value3 = 0x03
value4 = 0x04
value5 = 0x05
value6 = 0x06
value7 = 0x40
value8 = 0x80

def parse_byte(byte):
    return byte & value7, byte & 0x80, byte & 7

# Example 1
byte = value3 | value7
value7_set,value8_set,base_value = parse_byte(byte)
print("base_value = "+str(base_value))
if value7_set: print("value7_set")
if value8_set: print("value8_set")
print()

# Example 2
byte = value5
value7_set,value8_set,base_value = parse_byte(byte)
print("base_value = "+str(base_value))
if value7_set: print("value7_set")
if value8_set: print("value8_set")
print()

# Example 3
byte = value1 | value7 | value8
value7_set,value8_set,base_value = parse_byte(byte)
print("base_value = "+str(base_value))
if value7_set: print("value7_set")
if value8_set: print("value8_set")
print()
+5
4

value* -, value7 value8. , , :

mask0 = 0x07
mask1 = 0x40
mask2 = 0x80


def parse_byte(byte):
    return byte & mask2, byte & mask1, byte & mask0

bool - , . if bool .

,

format(value,'b').zfill(8)


format(value,'08b')
+10

, :

>>> x = 0b10001000

, :

>>> bit8 = bool(x & 0b10000000)
>>> bit7 = bool(x & 0b01000000)

, , :

>>> bdict = dict((1<<i, i+1) for i in range(6))
>>> bdict[x & 0b00111111]
4
+4

You do not need two other functions:

def parse_byte(byte):
    value7_set = byte & value7 == value7
    value8_set = byte & value8 == value8
    base_value =  byte & 7
    return value7_set,value8_set,base_value
+3
source

It is a bit verbose, but beautiful. The only change I would make is to simplify parse_byte:

def parse_byte(byte):

     value7_set = byte & value7 == value7
     value8_set = byte & value8 == value8
     base_value = mask_bits_on_byte(byte,value7 | value8)
     return value7_set,value8_set,base_value
+1
source

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