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How to take an array of strings and filter them?

I have an array of strings in jQuery. I have another array of keywords that I want to use to filter an array of strings.

Two of my arrays:

    var arr = new Array("Sally works at Taco Bell", "Tom drives a red car", "Tom is from Ohio", "Alex is from Ohio");

    var keywords = new Array("Tom", "Ohio");

How to filter an array arrusing an array keywordsin jQuery? In this situation, he filters out "Sally works at Taco Bell" and saves the rest.

Below is the actual code that I am using.

var keywords= [];
var interval = "";
var pointer = '';
var scroll = document.getElementById("tail_print");

$("#filter_button").click(
function(){
    var id = $("#filter_box").val(); 
    if(id == "--Text--" || id == ""){
        alert("Please enter text before searching.");
    }else{
        keywords.push(id);
        $("#keywords-row").append("<td><img src=\"images/delete.png\" class=\"delete_filter\" /> " + id + "</td>");
    }
}
);

$(".delete_filter").click(
function(){
   ($(this)).remove(); 
}
);

function startTail(){
clearInterval(interval);
interval = setInterval(
function(){
    $.getJSON("ajax.php?function=tail&pointer=" + pointer + "&nocache=" + new Date(),
        function(data){
            pointer = data.pointer;
            $("#tail_print").append(data.log);
            scroll.scrollTop = scroll.scrollHeight;
        });
}, 1000);
}

- . , , startTail(), $.getJSON() JSON, PHP, . . . , jQuery keywords, data.log JSON keywords, .

, . , - .

+5
7
$.grep( arr, $.proxy(/./.test, new RegExp(keywords.join("|"))));

jQuery:

arr.filter(/./.test.bind(new RegExp(keywords.join("|"))));
+8

jQuery "" grep

var arr = ["Sally works at Taco Bell", "Tom drives a red car", "Tom is from Ohio", "Alex is from Ohio"];
var keywords = ["Tom", "Ohio"];

var regex = new RegExp(keywords.join("|"));

result = $.grep(arr, function(s) { return s.match(regex) })
+4
var filtered = [];
var re = new RegExp(keywords.join('|'));

for (var i=0; i<arr.length; i++) {
    if (re.search(arr[i])) {
        filtered.append(arr[i]);
    }
}

UPDATE

jQuery, JavaScript-, , jQuery.

+1

. jQuery:

(function($) {

    $.foo = function(needle, haystack) {
        return $.grep(haystack, function () {
            var words = this.split(' '),
                flag = false
                ;

            for(var i=0; i < words.length; i++) {
                flag = $.inArray(words[i], needle);
                if (flag) { break; }
            }

            return flag;                
        });
    };

})(jQuery);

() , :

var bar = $.foo(keywords, arr);
+1

[ filter][1], . indexOf, , .

var arr = ["Sally works at Taco Bell", "Tom drives a red car", "Tom is from Ohio", "Alex is from Ohio"];
var keywords = ["Tom", "Ohio"];
var filtered = [];

for(var i = 0; i < arr.length; i++) {
    for(var j = 0; j < keywords.length; j++) {
        if (arr[i].indexOf(keywords[j]) > -1) {
            filtered.push(arr[i]);
            break;
        }
    }
}

console.log(filtered);

0

jQuery awesome powers:

var keywords = ["Tom", "Ohio"];
$(["Sally works at Taco Bell", "Tom drives a red car", "Tom is from Ohio", "Alex is from Ohio"]).filter(function(k, v) {
    return v.match("(" + keywords.join("|") + ")");
});
0
var keywords = ['Tom', 'Ohio'];
var arr = ['Sally works at Taco Bell', 'Tom drives a red car', 'Tom is from Ohio', 'Alex is from Ohio'];
var matcher = new RegExp(keywords.join('|'));
var newarr = [];
$.each(arr, function(index, elem) {
   if (elem.match(matcher)) {
      newarr.push(elem);
   }
});
console.log(newarr);

: http://jsfiddle.net/LQ92u/1/

0

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