Multiple DisplayMember Using Special Class

Question

I am trying to get a ListBox to display the concatenation of several rows of a table Accommodation.

Since I cannot edit the data source, I prepared a class AccommodationEntitythat contains both the source object Accommodationand the row that I want to display the ListBox.

However, for some reason, I cannot set the DisplayMember property in the ListBox, which thus displays jabber-jabber by default.

I set the list as follows:

accommodationList.DisplayMember = "textToShow";
// load and set up accommodation
List<AccommodationEntity> relatedAccommodations = 
    dt.listHolidayAccommodation(relatedHoliday);
accommodationList.DataSource = relatedAccommodations;
accommodationList.Refresh();

The class for objects stored in the data source is as follows:

class AccommodationEntity
{
    public accommodation classicAccommodation;
    public string textToShow;

    public AccommodationEntity(stay relatedStay)
    {
        this.classicAccommodation = relatedStay.accommodation;

        string from = relatedStay.dateFrom.ToString();
        string to = relatedStay.dateTo.ToString();
        string city = relatedStay.accommodation.location.ToString();
        string hotelName = relatedStay.accommodation.name.ToString();

        this.textToShow = hotelName + ", " + city + " (" + from + " - " + to + ")";
    }
}

} `

And finally, there is a method that performs a search (returns the correct objects):

public List<AccommodationEntity> listHolidayAccommodation(holiday selectedHoliday)
{
    List<AccommodationEntity> ubytovani = new List<AccommodationEntity>();

    var stays = from singleStay in selectedHoliday.stays
                select singleStay;

    foreach (stay singleStay in stays)
    {
        AccommodationEntity newStay = new AccommodationEntity(singleStay);
        ubytovani.Add(newStay);
    }

    return ubytovani;
}

, dataSource , - , DisplayMember "".

.

.

Answer 1

DisplayMember DisplayValue . "" / "" - Accomodation.

List<AccommodationEntity> relatedAccommodations = dt.listHolidayAccommodation(relatedHoliday);
accommodationList.DataSource = relatedAccommodations;
accommodationList.DisplayMember = "Name";
accommodationList.ValueMember = "Value";

UPDATE:

, textToShow Property, .

Answer 2

DisplayMember ValueMember ? DataSource MSDN, , .

UPDATE:

:

accommodationList.DisplayMember = "textToShow";
// load and set up accommodation
List<AccommodationEntity> relatedAccommodations = 
    dt.listHolidayAccommodation(relatedHoliday);
accommodationList.DataSource = relatedAccommodations;

:

// load and set up accommodation
List<AccommodationEntity> relatedAccommodations = 
    dt.listHolidayAccommodation(relatedHoliday);
accommodationList.DataSource = relatedAccommodations;
accommodationList.DisplayMember = "textToShow";