Does "delete pointer" simply mean "* pointer = 0"?

Question

# include <iostream>

int main()  
{  
using std::cout;
int *p= new int;

*p = 10;
cout<<*p<<"\t"<<p<<"\n";
delete p;
cout<<*p<<"\t"<<p<<"\n";

return 0;

}

Output:
10 0x237c010
0 0x237c010

Here, after removing p, why does the pointer p keep its value? Doesn't delete free pointer p?
What exactly does "free pointer" mean?
"Delete p" just means "* p = 0"? (What seems to be the output)

Answer 1

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Answer 4

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