PsExec for remote launch of a GUI application

I am trying to run a GUI application remotely using PsExec.

            ProcessStartInfo info = new ProcessStartInfo(@"<path to dir>");
            info.FileName = @"C:\<dirpath>\PsExec.exe";
            info.Arguments = @"\\" + "<COmputerName>" + " " + @"""C:\Program Files (x86)\<exepath>\<exename>.exe""";
            info.RedirectStandardOutput = true;
            info.UseShellExecute = false;
            info.RedirectStandardError = true;
            info.WindowStyle = ProcessWindowStyle.Maximized;

            Process o = Process.Start(info);

The problem is that the process starts remotely, but I do not see the GUI. I can only see this in the task manager. Is there any way to see the GUI on the remote computer?

EDIT 1: * Permissions *

  •   
  • Console.WriteLine (System.Environment.UserName.ToString ());
  • Console.WriteLine (Thread.CurrentPrincipal.Identity.Name.ToString ());
  • Console.WriteLine ("current winddentity" + System.Security.Principal.WindowsIdentity.GetCurrent (). Name.ToString ());

If I run the above line of code before starting the process, it gives:

Admin space DomainName \ Admin and I also registered it with an admin account on the remote computer.

* InteractiveMode * -i cmd, : -1073741502. # . , !

1.

+5
1

-i .

-i , . , .

info.Arguments = @"\\" + "<COmputerName>" + " -i " + @"""C:\Program F...
+3

All Articles