PatternSyntaxException

Question

After the line, it calls PatternSyntaxException:

Pattern.compile("*\\.*");

I want to create a template so that I can filter all files with a name in the following form: "*.*"

How can i do this?

Answer 1

To match all the strings with .in the name, follow these steps:

Pattern.compile(".*[.].*");

To break it:

• .* matches any number of arbitrary characters
• [.]corresponds to a point. (yes, \\.works too)
• .* matches any number of arbitrary characters

Demo:

Pattern p = Pattern.compile(".*[.].*");

System.out.println(p.matcher("hello.txt").matches()); // true
System.out.println(p.matcher("hellotxt").matches());  // false

Note that a single dot line "."also matches. To make sure that you have some characters in front and after a point, you can change *to +: .+[.].+.

---

The reason you get PatternSyntaxException:

* " , ". *, , .

Answer 2

* , . Java Pattern : http://docs.oracle.com/javase/6/docs/api/java/util/regex/Pattern.html

, :

Pattern.compile(".*\\..*");

Answer 3

, :

Pattern.compile("\\*\\.\\*");

, " ",

Pattern.compile(".*\\..*");

Answer 4

:

Pattern.compile("\\*\\.\\*");

* ( ) . , \\.

:

Pattern.compile("[*][.][*]");

* , [ ].

*.*, :

Pattern.compile(".+\\..+");

( ),

Pattern.compile(".+(\\..+)?");

Answer 5

, "." , :

Pattern.compile("[^\\.]*\\.[^\\.]*")

Answer 6

Pattern.compile(".*\\/.*\\..*"); . , . - . , , *, 0 . .
, C:/folder.1/folder.2/file.txt :
.* - C:/folder.1/folder.2 ( , /)
\/ - /
.* - file (, . ())
\\. - . ()
.* - txt ( . ( ))