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Join the tuple list

My code is as follows:

from itertools import groupby for key, group in groupby(warnstufe2, lambda x: x[0]): for element in group: a = element[1:4] b = element[4:12] c = [a,b] print(c)

When I type (c), I get something like this:

 [(a,b,c),(d,e,f)] [(g,h,i),(j,k,l)]

where a1 = (a, b, c) and b1 = (d, e, f) and a2 = (g, h, i) and b2 = (j, k, l). Of course there is a3 ... and b3 ... However, I need something like this:

 [(a,b,c),(d,e,f),(g,h,i),(j,k,l)]

I already tried the for loop through c:

 for item in c: list1 = [] data = list1.append(item)

But this did not help and led to:

 None None

based on this link: https://mail.python.org/pipermail/tutor/2008-February/060321.html

It seems to me that this is easy, but I am new to python and have not yet found a solution, despite a lot of reading. I appreciate your help!

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2 answers

try it

 from itertools import groupby result = [] for key, group in groupby(warnstufe2, lambda x: x[0]): for element in group: a = element[1:4] b = element[4:12] c = [a,b] result.append(c) print (result)
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Use itertools.chain() and the unpack list :

 >>> items = [[('a','b','c'),('d','e','f')], [('g','h','i'),('j','k','l')]] >>> >>> list(chain(*items)) [('a', 'b', 'c'), ('d', 'e', 'f'), ('g', 'h', 'i'), ('j', 'k', 'l')]
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