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How to extract relative url from absolute URL in Java

I have this site:

https://asd.com/somestuff/another.html

and I want to extract the relative part from it:

 somestuff/another.html

How to do it?

EDIT: I was offered the answer to the question, but the problem was to create an absolute URL from a relative who is not interested.

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5 answers

You can use the getPath() method of the URL object:

 URL url = new URL("https://asd.com/somestuff/another.html"); System.out.println(url.getPath()); // prints "/somestuff/another.html"

Now this leads only to the actual path. If you need additional information (anchor or parameters passed as get values), you need to call other accessors of the URL object:

 URL url = new URL("https://asd.com/somestuff/another.html?param=value#anchor"); System.out.println(url.getPath()); // prints "/somestuff/another.html" System.out.println(url.getQuery()); // prints "param=value" System.out.println(url.getRef()); // prints "anchor"

Possible use for generating relative URLs without a lot of code based on Hiru's answer :

 URL absolute = new URL(url, "/"); String relative = url.toString().substring(absolute.toString().length()); System.out.println(relative); // prints "somestuff/another.html?param=value#anchor"
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if you know that the domain will always be .com, then you can try something like this:

 String url = "https://asd.com/somestuff/another.html"; String[] parts = url.split(".com/"); //parts[1] is the string after the .com/
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The URL consists of the following elements (note that some optional elements are omitted): 1) scheme 2) host name 3) [port] 4) path 5) request 6) fragment Using the Java Java API, you can do the following:

 URL u = new URL("https://randomsite.org/another/randomPage.html"); System.out.println(u.getPath());

Edit # 1 If you see Chop's answer, if you have request elements in your url like

 ?name=foo&value=bar

Using the getQuery() method does not return the path to the resource, but only part of the query.

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try it

Use it globally not only for .com

  URL u=new URL("https://asd.in/somestuff/another.html"); String u1=new URL(u, "/").toString(); String u2=u.toString(); String[] u3=u2.split(u1); System.out.println(u3[1]); //it prints: somestuff/another.html
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You can do this using the snippet below.

  String str="https://asd.org/somestuff/another.html"; if(str.contains("//")) //To remove any protocol specific header. { str=str.split("//")[1]; } System.out.println(str.substring(str.indexOf("/")+1)); // taking the first '/'
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