How to compare two ArrayList <List <String>>
4 answers
You can try using the public resources of Apache CollectionUtils.retainAll : returns a collection containing all the items in collection1 that are also in collection2.
ArrayList commonList = CollectionUtils.retainAll(arrayList1, arrayList2);
If the size of commonList is equal to arrayList1
and arrayList2
, you can say that both lists are the same.
+3
You tried
arrayList1 .equals ( arrayList2 )
which is true if they contain the same elements in the same order
or
new HashSet(arrayList1) . equals (new HashSet(arrayList2))
if order doesn't matter
See http://www.docjar.com/html/api/java/util/AbstractList.java.html
+13
I think you can do it yourself without any dependencies.
public class ListComparator<T> { public Boolean compare(List<List<T>> a, List<List<T>> b) { if (a.size() != b.size()) { return false; } for (int i = 0; i < a.size(); i++) { if (a.get(i).size() != b.get(i).size()) { return false; } for (int k = 0; k < a.get(i).size(); k++) { if(!a.get(i).get(k).equals(b.get(i).get(k))) { return false; } } } return true; } }
And using
ListComparator<String> compare = new ListComparator<String>(); System.out.println(compare.compare(arrayList1, arrayList2));
I do not use the foreach operator because I read this post http://habrahabr.ru/post/164177/ (in Russian), but you can translate it into English.
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