We can use the fact that NaN != NaN :
In [1]: np.nan == np.nan Out[1]: False
Thus, comparing a column with itself will only return values ββother than NaN:
rs_gp.query('Col1 == Col1')
Demo:
In [42]: df = pd.DataFrame({'Col1':['aaa', np.nan, 'bbb', None, '', 'ccc']}) In [43]: df Out[43]: Col1 0 aaa 1 NaN 2 bbb 3 None 4 5 ccc In [44]: df.query('Col1 == Col1') Out[44]: Col1 0 aaa 2 bbb 4 5 ccc
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