Convert from UTF-8 to unicode C ++

Question

How to convert ú to a C ++ application, where the application receives the character as UTF-8% C3% BA encoding and saves it as the Unicode% FA equivalent. I just want to know how I will write code to complete this coding process.

Answer 1

I just wrote the code to do it yesterday ...

I'm not saying that this is the “ideal” way to do this, but it seems to work for all the test boxes I went through through (for this purpose I wrote both directions).

I will leave this for you to translate "% NN" to an integer value.

#include <iostream> #include <deque> std::deque<int> unicode_to_utf8(int charcode) { std::deque<int> d; if (charcode < 128) { d.push_back(charcode); } else { int first_bits = 6; const int other_bits = 6; int first_val = 0xC0; int t = 0; while (charcode >= (1 << first_bits)) { { t = 128 | (charcode & ((1 << other_bits)-1)); charcode >>= other_bits; first_val |= 1 << (first_bits); first_bits--; } d.push_front(t); } t = first_val | charcode; d.push_front(t); } return d; } int utf8_to_unicode(std::deque<int> &coded) { int charcode = 0; int t = coded.front(); coded.pop_front(); if (t < 128) { return t; } int high_bit_mask = (1 << 6) -1; int high_bit_shift = 0; int total_bits = 0; const int other_bits = 6; while((t & 0xC0) == 0xC0) { t <<= 1; t &= 0xff; total_bits += 6; high_bit_mask >>= 1; high_bit_shift++; charcode <<= other_bits; charcode |= coded.front() & ((1 << other_bits)-1); coded.pop_front(); } charcode |= ((t >> high_bit_shift) & high_bit_mask) << total_bits; return charcode; } int main() { int charcode; for(;;) { std::cout << "Enter unicode value:" << std::endl; std::cin >> charcode; auto x = unicode_to_utf8(charcode); for(auto c : x) { std::cout << "\\x" << std::hex << c << " "; } std::cout << std::endl; int c = utf8_to_unicode(x); std::cout << "reversed:" << std::dec << c << std::hex << " in hex:" << c << std::endl; } }