How to find the length of an item in a list?

Question

I am just starting with programming. I have a list of several lines, and now I need to print the largest (in length). Therefore, at first I just want to print the lengths of the elements. I tried things like this:

l = ("xxxxxxxxx", "yyyy","zz") for i in range(len(l): 

So how do I do this?

Answer 1

 l = ("xxxxxxxxx", "yyyy","zz") print(max(l, key=len)) 

First of all, you do not have a list, you have a tuple. however, this code will work for any sequence; both lists and tuples are sequences (as well as strings, sets, etc.). Thus, the max function accepts the key argument, which is used to sort the iteration elements. Thus, of all the elements l , one that has the maximum length will be selected.

Answer 2

To print the lengths of elements:

 elements = ["xxxxxx", "yyy", "z"] for element in elements: print len(element) 

I recommend you read some tutorials, for example http://docs.python.org/tutorial/

Answer 3

just ask max according to length

print max(["qsf","qsqsdqsd","qs"], key = len)

Answer 4

 >>> sorted(['longest','long','longer'],key=len)[-1] 'longest' 

UPDATE: SilentGhost's solution is much nicer.

Answer 5

The following code will print the largest line in the set:

 l = ["abcdev", "xx","abcedeerer"] len_0 = len(l[0]) pos = 0 for i in range(0,len(l)): if len(l[i]) > len_0: pos = i print l[pos] 

Answer 6

This code displays the len function above the list to get another list containing the length of each element.

 mylist = ("xxxxxxxxx", "yyyy","zz") len_mylist = map(len, mylist) max_position = len_mylist.index(max(len_mylist)) my_item = mylist[max_position] print('The largest item of my list is: ' + my_item) print('located at position: ' + str(max_position))