C # from a Ruby Wilson number

Question

Can someone help me convert this to C #. It literally hurts my brain.

http://www.evanmiller.org/how-not-to-sort-by-average-rating.html

require 'statistics2' def ci_lower_bound(pos, n, power) if n == 0 return 0 end z = Statistics2.pnormaldist(1-power/2) phat = 1.0*pos/n (phat + z*z/(2*n) - z * Math.sqrt((phat*(1-phat)+z*z/(4*n))/n))/(1+z*z/n) end 

What does it mean?

 Statistics2.pnormaldist(1-power/2) 

Answer 1

In case someone is interested ...

doing more search queries pnormaldist led me to this stackoverflow article: Objective-C Wilson Evaluation Interval Implementation

I converted this objective-c to C # mannually and it is completely untested

 public class WilsonScore { private static double pnormaldist(double qn) { double[] b = { 1.570796288, 0.03706987906, -0.8364353589e-3, -0.2250947176e-3, 0.6841218299e-5, 0.5824238515e-5, -0.104527497e-5, 0.8360937017e-7, -0.3231081277e-8, 0.3657763036e-10, 0.6936233982e-12 }; if (qn < 0.0 || 1.0 < qn) return 0.0; if (qn == 0.5) return 0.0; double w1 = qn; if (qn > 0.5) w1 = 1.0 - w1; double w3 = -Math.Log(4.0 * w1 * (1.0 - w1)); w1 = b[0]; int i = 1; for (; i < 11; i++) w1 += b[i] * Math.Pow(w3, i); if (qn > 0.5) return Math.Sqrt(w1 * w3); return -Math.Sqrt(w1 * w3); } public static double ci_lower_bound(int pos, int n, double power) { if (n == 0) return 0.0; double z = pnormaldist(1 - power / 2); double phat = 1.0 * pos / n; return (phat + z * z / (2 * n) - z * Math.Sqrt((phat * (1 - phat) + z * z / (4 * n)) / n)) / (1 + z * z / n); } } 

Answer 2

Have you tried Google?

http://social.msdn.microsoft.com/Forums/en-US/csharpgeneral/thread/fb3a8714-e458-4b7d-b669-1bd610258081/

The first answer is directly from MSDN.

Answer 3

This is the same library for Ruby:

https://github.com/abscondment/statistics2/blob/master/lib/statistics2.rb https://github.com/abscondment/statistics2/blob/master/lib/statistics2/version.rb