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Current Node Path in XDocument

Is it possible to get the path to the current XElement in an XDocument? For example, if I repeat the nodes in the document, is there a way to get the path to this node (XElement) so that it returns something like \ root \ item \ child \ currentnode?

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Nothing is built in there, but you can write your own extension method:

public static string GetPath(this XElement node) { string path = node.Name.ToString(); XElement currentNode = node; while (currentNode.Parent != null) { currentNode = currentNode.Parent; path = currentNode.Name.ToString() + @"\" + path; } return path; } XElement node = .. string path = node.GetPath();

This does not take into account the position of an element within its peer group.

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Depending on how you want to use XPath. In any case, you will need to go through the tree and build XPath along the way.

If you want to have a readable string for dispatching - just combining the names of the node nodes (see BrokenGlass suggestion) works fine

If you want to choose later in XPath

  • positional XPath (indicate the position of each node in its parent) is one option (something like // [3] / *). You should consider attributes as a special case, since there is no order defined for attributes
  • XPath with predefined prefixes (the namespace for the prefix must be stored separately) - / my: root / my: child [3] / o: prop1 / @ t: attr3
  • XPath with built-in namespaces when you want to get the received and portable XPath / * [name () = 'root' and namespace-uri () = 'http: //my.namespace'] / .... (see specification for name and uri namespace functions http://www.w3.org/TR/xpath/#function-namespace-uri )

Note that you must consider special nodes, such as comments and processing instructions, if you want a truly universal version of XPath for node inside XML.

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