Just started using JAX-WS. I created 2 test web services in a single WAR file as follows ....
package com.djs; import javax.jws.WebService; @WebService() public class AddTwoInts { public int performAdd(int firstNum, int secondNum) { return firstNum + secondNum; } }
A.....
package com.djs; import javax.jws.WebService; @WebService() public class SayHello { public String sayHello(String inwards) { return "Hello " + inwards; } }
This is my web.xml
<?xml version="1.0" encoding="UTF-8"?> <web-app xmlns="http://java.sun.com/xml/ns/j2ee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd" version="2.4"> <listener> <listener-class> com.sun.xml.ws.transport.http.servlet.WSServletContextListener </listener-class> </listener> <servlet> <servlet-name>jaxws</servlet-name> <servlet-class>com.sun.xml.ws.transport.http.servlet.WSServlet</servlet-class> </servlet> <servlet-mapping> <servlet-name>jaxws</servlet-name> <url-pattern>/</url-pattern> </servlet-mapping> </web-app>
This is sun-jaxws.xml
<?xml version="1.0" encoding="UTF-8"?> <endpoints xmlns='http://java.sun.com/xml/ns/jax-ws/ri/runtime' version='2.0'> <endpoint name='performAdd' implementation='com.djs.AddTwoInts' url-pattern='/AddTwoInts' /> <endpoint name='sayHello' implementation='com.djs.SayHello' url-pattern='/SayHello' /> </endpoints>
I deploy to Tomcat 7 and use http://localhost:8080/MyApp/AddTwoInts?wsdl to get the WSDL for AddTwoInts OK .... But when I do http://localhost:8080/MyApp/SayHello?wsdl , I I get an error on page 404.
Any advice is appreciated.
source share