Add namespace to default WSSE security object in Suds

Question

I understand how to add a header to a SOAP request. But this creates a header that does not match the one I need to pass. This returns this header:

<SOAP-ENV:Header> <wsse:Security mustUnderstand="true"> <wsse:UsernameToken> <wsse:Username>CABLE</wsse:Username> <wsse:Password>CABLE</wsse:Password> </wsse:UsernameToken> </wsse:Security> </SOAP-ENV:Header> 

However, I need to change the namespace of this header to pass a specific namespace for the Security object and the UsernameToken object. I cannot figure out how to override the default values.

 <soapenv:Header> <wsse:Security xmlns:wsse="http://schemas.xmlsoap.org/ws/2002/07/secext"> http://schemas.xmlsoap.org/ws/2002/07/secext <wsse:UsernameToken xmlns:wsu="http://schemas.xmlsoap.org/ws/2002/07/utility"> <wsse:Username>CABLE</wsse:Username> <wsse:Password Type="wsse:PasswordText">CABLE</wsse:Password> </wsse:UsernameToken> </wsse:Security> </soapenv:Header> 

Here is the Python code to generate the above

 security = Security() token = UsernameToken('CABLE', 'CABLE') security.tokens.append(token) client.set_options(wsse=security) 

Answer 1

Figured it out. Here's the answer. Just need to use the ns argument

 def createWSSecurityHeader(username,password): # Namespaces wsse = ('wsse', 'http://schemas.xmlsoap.org/ws/2002/07/secext') # Create Security Element security = Element('Security', ns=wsse) # Create UsernameToken, Username/Pass Element usernametoken = Element('UsernameToken', ns=wsse) uname = Element('Username', ns=wsse).setText(username) passwd = Element('Password', ns=wsse).setText(password) # Add Username and Password elements to UsernameToken element usernametoken.insert(uname) usernametoken.insert(passwd) security.insert(usernametoken) return security