Why doesn't the Spring MVC Project template in the SpringSource Tool Suite work with Tomcat?

Question

When Im creating a Spring MVC Template project in the SpringSource Tool and trying to run on a Tomcat server, I have this error:

WARN : org.springframework.web.servlet.PageNotFound - No mapping found for HTTP request with URI [/test/] in DispatcherServlet with name 'appServlet'. 

This is the default value: /test/src/main/java/ru/test/test/HomeController.java

 @Controller public class HomeController { private static final Logger logger = LoggerFactory .getLogger(HomeController.class); /** * Simply selects the home view to render by returning its name. */ @RequestMapping(value = "/", method = RequestMethod.GET) public String home(Locale locale, Model model) { logger.info("Welcome home! the client locale is " + locale.toString()); Date date = new Date(); DateFormat dateFormat = DateFormat.getDateTimeInstance(DateFormat.LONG, DateFormat.LONG, locale); String formattedDate = dateFormat.format(date); model.addAttribute("serverTime", formattedDate); return "home"; } } 

This is the default value: /test/src/main/webapp/WEB-INF/web.xml

 <?xml version="1.0" encoding="UTF-8"?> <web-app version="2.5" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"> <!-- The definition of the Root Spring Container shared by all Servlets and Filters --> <context-param> <param-name>contextConfigLocation</param-name> <param-value>/WEB-INF/spring/root-context.xml</param-value> </context-param> <!-- Creates the Spring Container shared by all Servlets and Filters --> <listener> <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class> </listener> <!-- Processes application requests --> <servlet> <servlet-name>appServlet</servlet-name> <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class> <init-param> <param-name>contextConfigLocation</param-name> <param-value>/WEB-INF/spring/appServlet/servlet-context.xml</param-value> </init-param> <load-on-startup>1</load-on-startup> </servlet> <servlet-mapping> <servlet-name>appServlet</servlet-name> <url-pattern>/</url-pattern> </servlet-mapping> </web-app> 

This is the default value / test / src / main / webapp / WEB -INF / spring / appServlet / servlet-context.xml

 <?xml version="1.0" encoding="UTF-8"?> <beans:beans xmlns="http://www.springframework.org/schema/mvc" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:beans="http://www.springframework.org/schema/beans" xmlns:context="http://www.springframework.org/schema/context" xsi:schemaLocation="http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc-3.0.xsd http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.0.xsd"> <!-- DispatcherServlet Context: defines this servlet request-processing infrastructure --> <!-- Enables the Spring MVC @Controller programming model --> <annotation-driven /> <!-- Handles HTTP GET requests for /resources/** by efficiently serving up static resources in the ${webappRoot}/resources directory --> <resources mapping="/resources/**" location="/resources/" /> <!-- Resolves views selected for rendering by @Controllers to .jsp resources in the /WEB-INF/views directory --> <beans:bean class="org.springframework.web.servlet.view.InternalResourceViewResolver"> <beans:property name="prefix" value="/WEB-INF/views/" /> <beans:property name="suffix" value=".jsp" /> </beans:bean> <context:component-scan base-package="ru.test.test" /> </beans:beans> 

By default, / test / src / main / webapp / WEB -INF / spring / root-context.xml is empty

Answer 1

I was getting the same problem and I solved it. Basically, when a Spring MVC project is created, Eclipse does not by default set src / main / webapp as the source directory. It should probably be the source directory, because then Eclipse will handle the files differently when it creates them.

By right-clicking on the "webapp" folder and clicking on "Build Path → Use as Source Folder", I solved this problem. The other comments here are incorrect: I did not need to change the RequestMapping URL or servlet url. '/' for both worked for my "localhost: 8080 / test / '.

Answer 2

It seems to me that the URL you are trying to click is "/ test /", and web.xml is only "/". You can change this to "/ *" if you want spring to handle all the URLs, and then you also had to change the home controller to "/ test".

Or you can simply click the URL "http: // localhost: 8080 /", which is the root URL that you mapped to the home controller.

Answer 3

After creating your Spring Template MVC Project in Eclipse, you must create it MANUALLY before running it on the server.

Answer 4

Found a solution!

When you start creating a project, you must define it. (pay attention to the third level of superapp )

To get into the application, the URL is http: // localhost: 8080 / superapp

It worked for me