Creating a chart in C ++

Question

Problem

I am doing a Fahrenheit conversion and vice versa.

All my code works perfectly, but I'm not sure how to make the diagram the teacher wants.

The output is from 0 to 100 degrees Celsius and from 32 to 212 degrees Fahrenheit.

Here is my code:

#include <iostream> #include <cstdlib> #include <iomanip> using namespace std; using std::setw; int i; int ftemp; int ctemp; int farToC(int a, int b); int celToF(int a, int b); int main (int argc, const char * argv[]) { cout << "Farenheit equivalents of Celsius temperatures: " << endl; for(i = 0; i < 5; i++) { cout << "Celsius Farenheit "; } cout << endl; for(i = 0; i < 101; i++) { cout << setw(7) << i << setw(8) << " " << celToF(i, ftemp)<< endl; } cout << endl; cout << "Celsius equivalents of Farenheit temperatures: " << endl; for(i = 0; i < 5; i++) { cout << "Fahrenheit Celsius "; } cout << endl; for(i = 32; i < 213; i++) { cout << setw(10) << i << setw(7) << " " << farToC(i, ctemp)<< endl; } cout << endl; } int farToC(int a, int b) { b = (a - 32) * 5 / 9; return b; } int celToF(int a, int b) { b = (a * 9/5) + 32; return b; } 

Here is my conclusion:

 Farenheit equivalents of Celsius temperatures: Celsius Farenheit Celsius Farenheit Celsius Farenheit Celsius Farenheit Celsius Farenheit 0 32 1 33 2 35 3 37 4 39 5 41 6 42 7 44 8 46 9 48 10 50 ... Celsius equivalents of Farenheit temperatures: Fahrenheit Celsius Fahrenheit Celsius Fahrenheit Celsius Fahrenheit Celsius Fahrenheit Celsius 32 0 33 0 34 1 35 1 36 2 37 2 38 3 39 3 40 4 41 5 42 5 ... 

Here's what my teacher wants: Celsius from 0 to 100 degrees.

 Farenheit equivalents of Celsius temperatures: Celsius Farenheit Celsius Farenheit Celsius Farenheit Celsius Farenheit Celsius Farenheit 0 32 25 77 50 122 1 33 26 78 51 123 2 35 27 80 52 125 3 37 28 82 53 127 4 39 29 84 54 129 5 41 30 86 55 131 6 42 31 87 56 132 7 44 32 89 57 134 8 46 33 91 58 136 9 48 34 93 59 138 10 50 35 95 60 140 ... 

And the same for Fahrenheit, but from 32 to 212 degrees ...

I know how to align numbers with words using setw (), but I'm not sure how to make columns.

Any ideas or suggestions would be appreciated!

---

Decision

Thank you all for your help. I figured this out for a moment.

 #include <iostream> #include <cstdlib> #include <iomanip> using namespace std; using std::setw; int i; int k; int ftemp; int ctemp; int farToC(int a, int b); int celToF(int a, int b); int main (int argc, const char * argv[]) { cout << "Farenheit equivalents of Celsius temperatures: " << endl; for(i = 0; i < 5; i++) { cout << "Celsius Farenheit "; } cout << endl; for(k = 0; k < 25; k++) { for(i = 0; i < 101; i+= 25) { cout << setw(7) << i+k << setw(10) << celToF(i+k, ftemp) << " " << setw(10); } cout<< endl; } cout << endl; cout << "Celsius equivalents of Farenheit temperatures: " << endl; for(i = 0; i < 5; i++) { cout << "Fahrenheit Celsius "; } cout << endl; for(k = 0; k < 45; k++) { for(i = 32; i < 213; i += 45) { cout << setw(10) << i+k << setw(8) << farToC(i+k, ctemp) << " " << setw(12); } cout << endl; } cout << endl; } int farToC(int a, int b) { b = (a - 32) * 5 / 9; return b; } int celToF(int a, int b) { b = (a * 9/5) + 32; return b; } 

My conclusion:

 Farenheit equivalents of Celsius temperatures: Celsius Farenheit Celsius Farenheit Celsius Farenheit Celsius Farenheit Celsius Farenheit 0 32 25 77 50 122 75 167 100 212 1 33 26 78 51 123 76 168 101 213 2 35 27 80 52 125 77 170 102 215 3 37 28 82 53 127 78 172 103 217 4 39 29 84 54 129 79 174 104 219 5 41 30 86 55 131 80 176 105 221 6 42 31 87 56 132 81 177 106 222 7 44 32 89 57 134 82 179 107 224 8 46 33 91 58 136 83 181 108 226 9 48 34 93 59 138 84 183 109 228 10 50 35 95 60 140 85 185 110 230 ... Celsius equivalents of Farenheit temperatures: Fahrenheit Celsius Fahrenheit Celsius Fahrenheit Celsius Fahrenheit Celsius Fahrenheit Celsius 32 0 77 25 122 50 167 75 212 100 33 0 78 25 123 50 168 75 213 100 34 1 79 26 124 51 169 76 214 101 35 1 80 26 125 51 170 76 215 101 36 2 81 27 126 52 171 77 216 102 37 2 82 27 127 52 172 77 217 102 38 3 83 28 128 53 173 78 218 103 39 3 84 28 129 53 174 78 219 103 40 4 85 29 130 54 175 79 220 104 ... 

Answer 1

You are already printing aligned columns, but they are not enough.

Start by printing

 Farenheit equivalents of Celsius temperatures: Celsius Farenheit Celsius Farenheit Celsius Farenheit Celsius Farenheit 0 32 0 32 0 32 0 32 1 33 1 33 1 33 1 33 ... 

and think about what you need to change in your program to print the chart you want.

Answer 2

You are already printing line by line and printing 25 lines. Now think about the relationships that each column has for the previous columns for each row:

 baseC toF(baseC) baseC+numRows toF(baseC+numRows) baseC+(2*numRows) ... baseC+1 toF(baseC+1) baseC+1+numRows toF(baseC+1+numRows) baseC+1+(2*numRows) ... 

The number of rows is the same value that you use to determine the number of loop cycles.

The baseC+X variable will take care of the baseC+X .

Note. This is pseudo code, so don't expect it to work directly :)