Eclipse gdb expression: what is shown in "default"?

Question

While executing C code in gdb using Eclipse, I noticed that for the variable char* sval gdb prints (on the "Expressions" tab):

• Expression: sval
• Type: char *
• Value: 0x7fffd9d79840 "BIDPRICE"

However, I know that the value must be something else (for example, "BIDZSPD"), because it was assigned a few lines above. Indeed, the value of sval[3] is "Z", as expected.

Then I noticed the following in the expression view, the same as when you mouse over a variable:

 Name : sval Details:0x7fffd9d79840 "BIDZSPD" Default:0x7fffd9d79840 "BIDPRICE" Decimal:140736848173120 Hex:0x7fffd9d79840 Binary:11111111111111111011001110101111001100001000000 Octal:03777773165714100 

It looks like different representations of the char pointer, but why are the details different from Default? Should I interpret "Default" as the previous value? Why is the default value displayed as the value of the expression and not the current value?

Answer 1

Full build fixed. This is one of the things to keep in mind when working with C ++: if things look really screwy (like gdb telling different values ​​at the same address), you need to bite the bullet and complete the assembly.