Why is the catch parameter implicitly final?

Question

catch (IOException|SQLException ex) { logger.log(ex); throw ex; } 

is that why ex implicitly definitive? What is the use of make implicitly definitively?

Answer 1

This is implicitly final because you do not need to modify the object that ex points to, especially in this case, when it can be either an IOException or SQLException , and thus the typing assignment will be difficult to determine by the compiler.