Groovy metaclass replace superclass method

Question

Is there a way to replace using a metaclass object, a super class method. Example:

class A { def doIt(){ two() println 'do it!' } protected two(){ println 'two' } } class B extends A{ def doLast(){ doIt() } } B b = new B(); b.doIt() /* * two * doit! */ b.metaClass.two = { println 'my new two!' } b.doIt(); /* * my new two! * do it! */ 

Answer 1

Since two and doIt declared in the same class, groovy will skip the meta object protocol for this call. You can override this behavior by marking the superclass as GroovyInterceptable , which causes all method calls to go through invokeMethod . For instance:

 class A implements GroovyInterceptable { def doIt(){ two() println 'do it!' } protected two(){ println 'two' } } class B extends A { def doLast(){ doIt() } } B b = new B() b.doIt() // prints two b.metaClass.two = { println 'my new two!' } b.doIt() // prints my new two!