Is there a faster way to get the colors on the screen?

Question

I have a piece of code, and what it does is find the colors of the image (or section of the screen), and if the color of RG and B is greater than 127, then it puts 1 in the corresponding position of the 2D int array. Here is the segment that I have now, but it is obviously very slow. Is there a better way to do this?

private void traceImage(){ try{ Robot r = new Robot(); b = new int[470][338]; for(int y = 597; y < 597+469; y++) { for(int x = 570; x < 570+337; x++) { if(r.getPixelColor(x,y).getRed() > 127 && r.getPixelColor(x,y).getGreen() > 127 && r.getPixelColor(x,y).getBlue() > 127) { b[y-597][x-570] = 1; } else { b[y-597][x-570] = 0; } } } } catch(Exception ex){System.out.println(ex.toString());} } 

There should be a faster way to do this using the above values. b is an int array, and it is initialized in this segment. r is the robot that I use to find the color of a pixel on the screen. x and y should be clear.

Thanks to Micker! This is the end result I got based on your answer:

 private void traceActionPerformed(java.awt.event.ActionEvent evt) { try{ Robot r = new Robot(); BufferedImage image = r.createScreenCapture(new Rectangle(597,570,470,337)); b = new int[image.getWidth()][image.getHeight()]; for(int y=0;y<image.getWidth();y++){ for(int x=0;x<image.getHeight();x++){ if(image.getRGB(y,x)==-1){ b[y][x]=0; } else{ b[y][x]=1; } } } System.out.println("Done"); } catch(Exception ex){System.out.println(ex.toString());} } 

-1 in the if else expression apparently finds the value of the black pixels as I wanted.

Answer 1

You must use Robot.createScreenCapture () to capture the entire subimage in one go.

Then you can quickly request individual pixels in this image. using BufferedImage.getRGB (x, y)

Interestingly, your particular operation has a very fast bitwise implementation: just do ((rgb & 0x808080) == 0x808080)