Groovy script executable

Question

I would like to do a portable groovy script wrapping and I inserted in the first line:

#!/usr/bin/env groovy 

The problem occurs when the script is run outside its directory, it cannot find the library. I came from the python world and imports everything into python, deciding on the path of the script. In groovy, it seems to me that I should specify -classpath, but I cannot do this in the first #! line.

Any suggestions for resolving it?

Answer 1

If the libraries are stored in the Maven repository, accessible where you want to run it, one solution would be to use Grape to grab the libraries.

This has several advantages:

• You do not need to worry about classpath at all
• You do not need to distribute libraries - just make sure Groovy is available on the client
• Libraries are downloaded only once, so even if you update the application, you only need to redistribute the .groovy file.

A simple example:

 #!/usr/bin/env groovy @Grab(group='commons-io', module='commons-io', version='2.3') import org.apache.commons.io.FileUtils ... use FileUtils like normal ... 

There are already many existing libraries at mvnrepository.com .

Even if you have non-public libraries, it is relatively easy to host your own libraries in a local / private repository .