I use PyCrypto to encrypt a binary using AES in CBC mode (Python 3.2.3 64-bit and PyCrypto 2.6). Using this code: http://eli.thegreenplace.net/2010/06/25/aes-encryption-of-files-in-python-with-pycrypto/
But running the following error: ValueError: IV should be 16 bytes long.
Here is the code:
def encryptFile(key, in_filename, out_filename=None, chunksize=64*1024): """ Encrypts a file using AES (CBC mode) with the given key. key: The encryption key - a string that must be either 16, 24 or 32 bytes long. Longer keys are more secure. in_file: Input file out_file: If None, a StringIO will be returned. chunksize: Sets the size of the chunk which the function uses to read and encrypt the file. Larger chunk sizes can be faster for some files and machines. chunksize must be divisible by 16. """ if not out_filename: out_filename = in_filename + '.enc' iv = ''.join(chr(random.randint(0, 0xFF)) for i in range(16)) encryptor = AES.new(key, AES.MODE_CBC, iv) filesize = os.path.getsize(in_filename) with open(in_filename, 'rb') as infile: with open(out_filename, 'wb') as outfile: outfile.write(struct.pack('<Q', filesize)) outfile.write(iv) while True: chunk = infile.read(chunksize) if len(chunk) == 0: break elif len(chunk) % 16 != 0: chunk += ' ' * (16 - len(chunk) % 16) outfile.write(encryptor.encrypt(chunk))
I tried searching and experimenting, but can't get it to work. Python is pretty new to me, and it's also encryption. Any help would be greatly appreciated. Thanks in advance.
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