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How to convert a Counter object to a useful list of pairs?

The code I have is:

from collections import Counter c=Counter(list_of_values)

returns:

 Counter({'5': 5, '2': 4, '1': 2, '3': 2})

I want to sort this list by numerical (/ alphabetic) order by position, not by the number of occurrences. How can I convert this to a list of pairs, for example:

 [['5',5],['2',4],['1',2],['3',2]]

Note: if I use c.items (), I get: dict_items ([('1', 2), ('3', 2), ('2', 4), ('5', 5)]) that doesn't help me ...

Thanks in advance!

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5 answers

Err ...

 3>> list(collections.Counter(('5', '5', '4', '5')).items()) [('5', 3), ('4', 1)]
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If you want to sort by number / alphabetically ascending:

 l = [] for key in sorted(c.iterkeys()): l.append([key, c[key]])
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You can simply use sorted() :

 >>> c Counter({'5': 5, '2': 4, '1': 2, '3': 2}) >>> sorted(c.iteritems()) [('1', 2), ('2', 4), ('3', 2), ('5', 5)]
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Convert the counter into a dictionary, and then divide it into two separate lists, for example:

 c=dict(c) key=list(c.keys()) value=list(c.values())
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 >>>RandList = np.random.randint(0, 10, (25)) >>>print Counter(RandList)

outputs something like ...

 Counter({1: 5, 2: 4, 6: 4, 7: 3, 0: 2, 3: 2, 4: 2, 5: 2, 9: 1})

And with that ...

 >>>thislist = Counter(RandList) >>>thislist = thislist.most_common() >>>print thislist [(1, 5), (2, 4), (6, 4), (7, 3), (0, 2), (3, 2), (4, 2), (5, 2), (9, 1)] >>>print thislist[0][0], thislist[0][1] 1 5
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