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How to call external CSS in the presence of embedded and internal?

If on my webpage I have all three css defined for div

  • Built in
  • Interior
  • external

I know that the browser first searches for 1) Inline then for 2) Internal and last, it searches for external css.

but I want to call only external css, how will this be done ??? Can I do this via !important or is there another way?

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3 answers

It is best to put everything in an external css file. If you must have an inline style, make sure that you have only those that are not yet defined in your external style sheet. I dont duplicate / redefine the style. for example, if your css file has the following:

 div { padding: 5px; }

then does not have the following inline style.

 <div style="padding-right:2px;" />

Just put it in a css file

 div { padding: 5px 2px 5px 5px; }

As you said, you can use !important if you have to override the style for only one page, which does not apply to other pages on your site.

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There is no difference between internal and external style sheets. What styles are applied depends on:

  • Specificity
  • Declaration Procedure

Inline styles are the most specific, followed by identification rules (#), then class rules (.), Then element rules.

For two rules that have the same specificity, for example div .main and span.title , both rules apply, but the last one prevails when they specify the same properties.

The only way around the priority is to use !important .

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1) Inline then for 2) Internal and last, it looks for external css.

Not. There is no difference in priority between CSS included in <style> and CSS included in <link> .

but I want to call only external css, how will this be done ???

You cannot ignore CSS included through <style> or CSS included through the style attribute.

Can i make it through! is it important or is there another way?

You can apply !important to each rule, and then hope that no rule included via <style> or style also has !important ... but this way is crazy.

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