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Cancel form upload

I have the following code:

Call of the second form

private void updateToolStripMenuItem_Click(object sender, EventArgs e) { Update fm = new Update(); fm.ShowDialog(); }

This is the constructor

  public Update() { InitializeComponent(); }

This is load

  private void Update_Load(object sender, EventArgs e) { String ver = checkver(); if (ver == "update") { if (RemoteFileExists(dlUrl) == true) { WebClient webClient = new WebClient(); webClient.DownloadFileCompleted += new AsyncCompletedEventHandler(Completed); webClient.DownloadProgressChanged += new DownloadProgressChangedEventHandler(ProgressChanged); webClient.DownloadFileAsync(new Uri(dlUrl), ""); } else MessageBox.Show("An error occurred. Please try later."); } else if (ver == "newest") { MessageBox.Show("You are currently using the newest version."); this.Close(); } else { this.Close(); } }

My problem is that when the result of the function is 2 or 3, the form is displayed in milliseconds and then it closes (blinks). I want the form not to blink. Is it possible?

I tried using this.Hide () , this.Visible = False , but nothing helped.

EDIT: I put the source code EDIT2: add more code

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6 answers

You can hide the form before loading, and then return it to the visible conditions in if else . eg:

  MyForm myForm = new MyForm(); myForm.Opacity = 0; myForm.Show();

And then:

 if (ver == "update") { if (RemoteFileExists(dlUrl) == true) { myForm.Opacity = 100; ... } else MessageBox.Show("An error occurred. Please try later."); } else if (ver == "newest") { MessageBox.Show("You are currently using the newest version."); this.Close(); } else { this.Close(); }
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The best way to do this is:

 private void Form_Load(object sender, EventArgs e) { switch(funct()) { case 2: this.BeginInvoke(new MethodInvoker(this.Close)); break; case 3: this.BeginInvoke(new MethodInvoker(this.Close)); break; default: MessageBox.Show("Something"); } }
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You probably should do whatever you do before you decide to open the form first.

So something like:

 if(funct() == "1") { var form = new Form(); form.ShowDialog(); }
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I assume Update_Load is your FormLoad handler? This is called after . Your form has been displayed. If you do not want to display it, it is too late. Change updateToolStripMenuItem_Click to this:

 String ver = checkver(); if (ver == "update") { if (RemoteFileExists(dlUrl)) { Update fm = new Update(); fm.ShowDialog(); } else MessageBox.Show("An error occurred. Please try later."); } else if (ver == "newest") { MessageBox.Show("You are currently using the newest version."); }

And change your Update_Load to:

 WebClient webClient = new WebClient(); webClient.DownloadFileCompleted += new AsyncCompletedEventHandler(Completed); webClient.DownloadProgressChanged += new DownloadProgressChangedEventHandler(ProgressChanged); webClient.DownloadFileAsync(new Uri(dlUrl), "");
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Perhaps first hide it, and then show only if the function () == "1":

 private void Form_Load(object sender, EventArgs e) { this.Close(); if (funct() == "1") MessageBox.Show("Something"); }
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try it

 private void Form_Load(object sender, EventArgs e) { switch(funct()) { case 2: this.Close(); break; case 3: this.Close(); break; default: MessageBox.Show("Something"); } }
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