Search for duplicate patterns in a string

Question

Well, the problem is that given the fraction eg:1/3 answer 0.3333333 should be represented as 0.(3) and 0.2325555 as 0.232(5) I figured out a way to split the line when one digit is repeated:

using re.findall(r'^(.+?)((.)\3+)$', '42344444' )[0][:-1] (ignoring 0. before the number)

but I want to know how to do this if the template is 0.324324324.. to get 0.(324)

Answer 1

add + after . in the repeating part:

 >>> re.findall(r'^(.+?)((.+)\3+)$', '42344343434' )[0][:-1] ('42344', '343434')