How can I ensure that the template parameter used implements some interface in C ++?

Question

I don't think this is possible in C ++, what parameters do I need to simulate behavior?

+4

dchhetri Dec 6 '12 at 18:26

3 answers

Use std::is_base_of as:

 template<typename T> class A { static_assert(std::is_base_of<IMyInterface, T>::value, "T must derive from IMyInterface"); };

You can also use a function template.

+9

Nawaz Dec 6 '12 at 18:29

Some polymorphic interfaces or some static interface? The latter can be checked using the "Concept of increasing . "

+3

ipc Dec 6 '12 at 18:30

Synxis · Accepted Answer · 2012-12-06T18:29:55+0000

You can use std::is_base_of<YourInterface, YourParameter> and make a mistake if the result is false . Remember this is C ++ 11.