It seems like it should be a duplicate, but I could not find it in the SO search. I know this has appeared many times. But there is a condition for this:
require(fortunes) fortune("every question") Lastly, by what we could call the 'Liaw-Baron principle', every question that can be asked has in fact already been asked. -- Dirk Eddelbuettel (citing Andy Liaw and Jonathan Baron opinion on unique questions on R-help) R-help (January 2006) polygon(x= c(X[order(X)], rev(X[order(X)]) ), # both x and y go "out" in order; y=c(L[order(X)], rev(U[order(X)])), # and then come "back in reverse order col=rgb(1,0,0,0.3) ) # transparent pink. > plot(X,Y, pch="+") > abline(reg, col="red") > polygon(x= c(X\[order(X)\], rev(X\[order(X)\]) ), y=c(L\[order(X)\],rev(U\[order(X)\])), col=rgb(1,0,0,0.3) )

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