Html conditional compilation disabled in MVC C #

Question

I wrote this function

<script type="text/javascript"> function saveDelivery() { alert("tttt") var model = @Html.Raw(Json.Encode(Model)); //errror $.ajax({ type: 'POST', url: '@Url.Action("SaveDelivery", "Business")', contentType: 'application/json; charset=utf-8', data: JSON.serialize(model), success: function (result) { }, error: function (xhr, ajaxOptions, thrownError) { alert(xhr.status); alert(thrownError); } }); } 

but there is an error on

 var model = @Html.Raw(Json.Encode(Model)); 

says conditional compilation is turned off How to do this?

Answer 1

You can use the Html extension to output script tags. It will also help deal with Intellisense issues in Visual Studio.

 public static class Extensions { public static IHtmlString BeginScript(this HtmlHelper htmlHelper) { return new HtmlString("<script type=\"text/javascript\">"); } public static IHtmlString EndScript(this HtmlHelper htmlHelper) { return new HtmlString("</script>"); } } 

And then, in your opinion:

 @Html.BeginScript() // JavaScript... var model = @Html.Raw(Json.Encode(Model)); // More JavaScript... @Html.EndScript() 

NOTE. You need to add the namespace of your extension class to the <system.web.webPages.razor> element in web.config (the one that is in the views folder)

Answer 2

There are two options:

• Do not care, you are confident in your code (this is a warning)
• Do something like this: var model = '@Html.Raw(Json.Encode(Model)) ', but you probably have to change it to: var model = JSON.parse('@Html.Raw(Json.Encode(Model))')

Answer 3

mvc 4 link is missing for Json.Encode

first add system.web.helper refrence
then right click on this refrence property and change Copy Locaal = false to true and run your code using json.Encode