Unable to evaluate script arguments from function

Question

I started writing shell scripts again, and I found myself in a situation where I often have to write a debugging echo to keep track of what the script is doing. Easy, as I usually did, was to write something like this:

#!/bin/bash
myVar = 'Erractic Nonesense'
echo "myVar: $myVar" 

==> myVar: Erractic Nonesense

This worked fine and was pretty simple, but writing it for every variable that I wanted to track was tedious, and, as a person who thinks that having less code to create more materials, I wrote myself a function:

#!/bin/bash
dbg() # $msg
{
    echo "$@: ${!@}" 
}

myVar = 'Erractic Nonesense'
dbg myVar

==> myVar: Erractic Nonesense

This works fine for regular variables, but does not work for script arguments ($ 1, $ 2, etc.). Why?

==> $ ./myScript 123

#!/bin/bash
...
dbg 1 # This is the bugger in question.

==> 1: 1

And also, how can this be circumvented?

EDIT

Thanks to Barmar, I now see why he behaves this way, but the second question remains.

EDIT 2

koodawg, . . , . EDIT 4

3

, EDIT 2 set +-x .

EDIT 4

​​, , . .

RX_INTEGER='^[0-9]+$'
DBG_SCRIPT_ARGS=( "$0" "$@" )
DBG_PADDING="        " # tabs of 8 spaces
dbg() # $msg | OUT$args OUT$res
{    
    args=$@
    [[ $args =~ $RX_INTEGER ]] && res="${DBG_SCRIPT_ARGS[args]}" || res="${!@}"
    printf "%s%s\`%s\`\n" "$args:" "${DBG_PADDING:$(((${#args}-1)%${#DBG_PADDING}))}" 
}

Answer 1

script. - :

for argz in `echo $*`
do
    dbg ${argz}
done