How to get Python 2 to raise an exception when comparing different types?

Question

Comparing strings with ints in Python 2.7.2 looks very incompatible:

x = '12'; y = 3
print x > y      # True
x = 12; y = '3'
print x > y      # False

According How does Python compare string and int? in Python 3, this will throw an exception. Is there a way to make Python 2 already behave like this? Looking at __future__I could not understand if there is such an opportunity.

Answer 1

No. Your choice:

• Record and use wrapper classes that result from unwanted mappings.

• Record and use custom comparison functions instead of regular operators.

• - MacroPy, .

• .

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• Python 3, Python 3.

Answer 2

( , C), . TypeError .

, Python 2, Python 3, .