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Python function to check palindrome

Below is the code to check if the list is a palindrome or not. It gives the correct result for 983. Where am I going wrong?

def palindrome(num):
    flag=0
    r=num[::-1]
    for i in range (0, len(num)-1):
        if(r[i]==num[i]):
            flag=1
        else:
            flag=0
    return flag
+4
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9 answers

You must return as soon as a mismatch occurs. In addition, you just need to repeat up to half the length:

def function(...):
    ...
    for i in range (0, (len(num) + 1) / 2):
        if r[i] != num[i]:
            return False
    return True

By the way, you do not need this loop. You can simply do:

def palindrome(num):
    return num == num[::-1]
+21
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That would be easier:

def palindrome(num):
    if num[::-1] == num:
       return True
    else:
       return False
+4
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for , , . , "38113" True, flag ​​ True "38113" "31183" ( 3, ).
, False , ; - True, :

def palindrome(num):
    r = num[::-1]
    for i in range (0, len(num)-1):
        if(r[i] != num[i]):
            return False
    return True

, -, python - .

0

For writing purposes only, and for those who are looking for a more algorithmic way to check if a given line is a palindrome, there are two ways to achieve the same (using whileand loops for):

def is_palindrome(word):

    letters = list(word)    
    is_palindrome = True
    i = 0

    while len(letters) > 0 and is_palindrome:       
        if letters[0] != letters[-1]:
            is_palindrome = False
        else:
            letters.pop(0)
            if len(letters) > 0:
                letters.pop(-1)

    return is_palindrome

And .... second:

def is_palindrome(word):

    letters = list(word)
    is_palindrome = True

    for letter in letters:
        if letter == letters[-1]:
            letters.pop(-1)
        else:
            is_palindrome = False
            break

    return is_palindrome
0
source 
str1=str(input('enter string:'))
save=str1
revstr=str1[::-1]
if save==revstr:
     print("string is pailandrom")
else:
     print("not pailadrom")
0
source 
# We are taking input from the user.
# Then in the function we are reversing the input i.e a using 
# slice     [::-1] and 
# storing in b
# It is palindrome if both a and b are same.

a = raw_input("Enter to check palindrome:") 
def palin():
    #Extended Slices to reverse order.
    b = a[::-1]
    if a == b:
        print "%s is palindrome" %a
    else:
        print "%s is not palindrome" %a
palin()
0
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this would be much simpler:

def palindrome(num):
    a=num[::-1]
    if num==a:
        print (num,"is palindrome")
    else:
        print (num,"is not palindrome")

x=input("Enter to check palindrome:")
palindrome(x)
0
source 
a="mom"
b='mom'[::-1]  # reverse the string
if a==b:  # if original string equals to reversed
    print ("palindrome ")
else:
    print ("not a palindrome ")
-1
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def palindrome(a):
     a=raw_input('Enter :')
     b=a[::-1]
     return a==b
-2
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