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Creating a nested dictionary for python word

I have a list of words, and I would like to save them in a nested dictionary.

Here is a list of examples: -

words = ['Apple','Ape','Bark','Barn']

The dictionary that I want to create is as follows: -

{'A':{'P':{'E':{},
           'P':{'L':{'E':{}}}}},
 'B':{'A':{'R':{'K':{},'N':{}}}}}

Words are case insensitive.

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1 answer

Use instead collections.defaultdict():

from collections import defaultdict

def tree():
    return defaultdict(tree)

nested = defaultdict(tree)

for word in words:
    node = nested
    for char in word:
        node = node[char.upper()]

, defaultdict, , factory . factory tree(), defaultdict() factory, .

:

>>> from collections import defaultdict
>>> def tree():
...     return defaultdict(tree)
... 
>>> nested = defaultdict(tree)
>>> words = ['Apple','Ape','Bark','Barn']
>>> for word in words:
...     node = nested
...     for char in word:
...         node = node[char.upper()]
... 
>>> nested
defaultdict(<function tree at 0x114e62320>, {'A': defaultdict(<function tree at 0x114e62320>, {'P': defaultdict(<function tree at 0x114e62320>, {'P': defaultdict(<function tree at 0x114e62320>, {'L': defaultdict(<function tree at 0x114e62320>, {'E': defaultdict(<function tree at 0x114e62320>, {})})}), 'E': defaultdict(<function tree at 0x114e62320>, {})})}), 'B': defaultdict(<function tree at 0x114e62320>, {'A': defaultdict(<function tree at 0x114e62320>, {'R': defaultdict(<function tree at 0x114e62320>, {'K': defaultdict(<function tree at 0x114e62320>, {}), 'N': defaultdict(<function tree at 0x114e62320>, {})})})})})
>>> def print_nested(d, indent=0):
...     for k, v in d.iteritems():
...         print '{}{!r}:'.format(indent * '  ', k)
...         print_nested(v, indent + 1)
... 
>>> print_nested(nested)
'A':
  'P':
    'P':
      'L':
        'E':
    'E':
'B':
  'A':
    'R':
      'K':
      'N':

A defaultdict Python , , , .

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