How to find the number of rows in a dynamic 2D char array in C?

Question

I have an input function, for example:

int func(char* s[])
{
    // return number of rows in the character array s
}

where the char array is provided randomly, for example: {"sdadd", "dsdsd", "dsffsf", "ffsffsf"}.

Here the output should be 4 for the example above.

Answer 1

Passing string arrays requires more information ...

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                                    //and only when declared and defined in scope of the call 

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Answer 2

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  #include<stdio.h>
  int main(int argc, char *argv[])
  {
      int i;
      for(i=0; argv[i] != NULL; i++)
      {
          printf("%s\n", argv[i]);
      }
      return 0;
  }
  

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Answer 3

int size = sizeof(s)/sizeof(s[0]);

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