What is the concatenation of this language with you?

Given the following language:

L1 = { (ab)n | n ≥ 0 }

I.e L1 = { ε ab, abab, ababab, abababab, ... }

The question is to find the language .L12

I assume that it is equal . It's right? If so, how can I prove it? If not, why not?{ (ab)2n | n ≥ 0 }

Thanks!

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1 answer

The language L 1 2 is the language of all lines of the form xy, where x & in; L 1 and y & in; L <sub> 1sub>. Note that x and y need not be the same string; they can be selected independently.

, , y = & epsilon;, & epsilon; = (ab) 0. L 1 L 1 2 & epsilon;.

, , L 1 2 L 1. w & in; L < > 1 > 2. xy x, y & in; L < > 1 > . , w = xy = (ab) n (ab) m n m. , w = (ab) n + m w L 1.

, L 1 & subseteq; L 1 2 L 1 2 & subseteq; L 1, , L 1= L 1 2. , L 1 2 - , L 1.

, !

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