From jQuery docs javascript guide :
Since the local area works through functions, any defined functions inside another have access to the variables defined in the external function:
function outer() {
var x = 5;
var y = 2;
function inner() {
console.log( x );
debugger;
}
inner();
}
outer()
The console starts with debugger:
> x
5
> y
ReferenceError: y is not defined
Since the variables defined in the function outercan be used by the function inner(for example, xor y), why can't the debugger call the variable y?
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, ,, y ? ( , , outer.y)
:
-, javascript. Python pdb, , :
def outer():
x = 5
y = 2
def inner():
print x
import pdb; pdb.set_trace()
inner()
outer()
(Pdb) x
5
(Pdb) y
*** NameError: 'y' is not defined