Radio button uncheck the button again

Question

I have many switches that capture the value from my database, and if it is set to "1", I set the switch.

If the switch is set and the user clicks it again, I still want to clear this button. Does anyone have an idea?

$radio1 captures data from the database and will be either 0, 1, or 2

<input value="1" name="radio1" type="radio"<?php if($radio1==1){echo " checked";} ?>>
<input value="2" name="radio2" type="radio"<?php if($radio1==2){echo " checked";} ?>>

Varun Malhotra Answer slightly modified: I changed 2 lines of code that worked a little better for me. But overall, Varuna's answer was PERFECT!

$('input[type="radio"]').click(function(){
    var $radio = $(this);

    // if this was previously checked
    if ($radio.data('waschecked') == true)
    {
        $radio.prop('checked', false);
        $radio.data('waschecked', false);
    }
    else
    {
         $radio.prop('checked', true);
         $radio.data('waschecked', true);
    }

    // remove was checked from other radios
    $radio.siblings('input[type="radio"]').data('waschecked', false);
});

Answer 1

, :

$(function(){
    $('input[name="rad"]').click(function(){
        var $radio = $(this);

        // if this was previously checked
        if ($radio.data('waschecked') == true)
        {
            $radio.prop('checked', false);
            $radio.data('waschecked', false);
        }
        else
            $radio.data('waschecked', true);

        // remove was checked from other radios
        $radio.siblings('input[name="rad"]').data('waschecked', false);
    });
});

<input type="radio" name="rad" id="Radio0" checked="checked" data-waschecked="true" />

JSFIDDLE DEMO

UPDATE:

 $(function(){
        $('input[name="rad"]').click(function(){
            var $radio = $(this);

            // if this was previously checked
            if ($radio.data('waschecked') == true)
            {
                $radio.prop('checked', false);
                $radio.data('waschecked', false);
            }
            else
                $radio.data('waschecked', true);

            // remove was checked from other radios
            $radio.siblings('input[type="radio"]').data('waschecked', false);
        });
    });

, - , , , prop, .

Answer 2

, . . .

$("input[type=radio]").each(function() {
    var secondClick = true;
    $(this).change(function() {
        secondClick = false;
    });
    $(this).click(function() {
        if (secondClick) {
            $(this).prop("checked", false);
        }
        secondClick = true;
    });
});

JSFIDDLE DEMO

Answer 3

This should work more generally than other solutions, as it handles cases where all the radio stations are not in the same parent.

var $radios = $('input[type="radio"]');
$radios.click(function () {
  var $this = $(this);
  if ($this.data('checked')) {
    this.checked = false;
  }
  var $otherRadios = $radios.not($this).filter('[name="'
                                               + $this.attr('name') + '"]');
  $otherRadios.prop('checked', false).data('checked', false);
  $this.data('checked', this.checked);
});

Answer 4

$("input[type=radio]").on('click', function () {
    if ($(this).is(':checked')) {
        $(this).prop("checked", false);
    } else {
        $(this).prop("checked", true);
    }
});