Javascript sorting method that processes null values

Question

I have a list of objects where I want to sort objects based on a field that I know. I can use sorting methods. When the comparison field has zero values, no sorting occurs, how to solve this problem?

http://jsfiddle.net/mailtoshebin/kv8hp/

var arrOfObj = [
    {
        "Name": "Zak",
        "Age": 25
    },
    {
        "Name": "Adel",
        "Age": 38
    },
    {
        "Name": null,
        "Age": 38
    },
    {
        "Name": "Yori",
        "Age": 28
    }
];

sortArrOfObjectsByParam(arrOfObj, "Name");
alert("ASCENDING: " + arrOfObj[0].Name + ", " + arrOfObj[1].Name + ", " + arrOfObj[2].Name);

function sortArrOfObjectsByParam(arrToSort , strObjParamToSortBy  ) {
    if(sortAscending == undefined) sortAscending = true;  // default to true

    if(sortAscending) {
        arrToSort.sort(function (a, b) {

            return a[strObjParamToSortBy] > b[strObjParamToSortBy];
        });
    }
    else {
        arrToSort.sort(function (a, b) {
            return a[strObjParamToSortBy] < b[strObjParamToSortBy];
        });
    }
}

Answer 1

you can deal with null values ​​inside comp func:

    arrToSort.sort(function (a, b) {
         if (a[strObjParamToSortBy]==null) return 1
         if (b[strObjParamToSortBy]==null) return 0
        return a[strObjParamToSortBy] > b[strObjParamToSortBy];
    });