Golang casts multiple return value to match result name parameter

Question

Suppose I want to define a function with named result parameters, one of which is string. This function internally calls another function that returns a byte representation of such a string.

Is there a way to pass the result without using a temporary variable?

func main() {
    out, _ := bar("Example")
    fmt.Println(out)
}

func foo(s string) ([]byte, error) {
    return []byte(s), nil
}

func bar(in string) (out string, err error) {
    // is there a way to assign the result to out
    // casting the value to string in the same line
    // istead of using the tmp variable?
    tmp, err := foo(in)

    if err != nil {
        return "", err
    }
    return string(tmp), nil
}

The idea is that, if possible, I can potentially shorten the code to

func bar(in string) (out string, err error) {
    // assuming there is a way to cast out to string
    out, err := foo(in)
    return
}

Does it make sense?

Answer 1

. , . http://play.golang.org/p/bf4D71_rZF ,