Geek Answers Handbook

Why are some of the standard C ++ `operator <<` functions of the function reset their thread widths to 0?

As indicated in the section of [ostream.inserters.character]the C ++ standard, after a string charor string is inserted into a stream , the width of the stream is set to 0:

template<class traits>
  basic_ostream<char,traits>& operator<<(basic_ostream<char,traits>& out,
                                         const unsigned char* s);
Do lots of sensible and expected things...
Calls width(0).

Why width(0)does the C ++ standard dictate a call ?

What is the rationality of changing the width of the flows, and not reselling it to its original value? (As far as I know, all other stream properties are saved by stream insert statements.)

There is a related question here that demonstrates the confusion this causes, but does not explain why the standard dictates this behavior.

+4
1

, "" operator<< , (21.4.8.9). . ++ Tony D

+1

More articles:


All Articles