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JSON returns empty response on FireFox and Safari (Windows Vista)

SOLVED:

The problem is the security of Firefox 6.0.2. I changed my request URL from: http://mysite.com/ajax/request to / ajax / request and its work.

If you need to use cross domains, you need to use jsonp as your data type.

Thank you very much evildead

My JSON request to my server returns an empty response. This only happens on Firefox 6.0.2 and Safari on a Windows Vista computer.

The output is generated by a php script and has json / application headers.

This returns an empty answer:

    $('#ajaxcall').click(function(){
var ts = new Date().getTime();
var urlz = $('#targeturl').val()+'/'+ts;
var dataString = $("#datazz").val();
$.ajax({  
    type: "POST", url: urlz, data: "data="+dataString, 
    success: function(data){  
        var obj = jQuery.parseJSON(data);

        for (var i = 0; i < obj.length; i++) {
            var object = obj[i];
            for (property in object) {
            var s = property + "=" + object[property] + "<br>";
                $("#console").after(s);
            }
        }
    }  
});
});

Besides:

$( "#tags" ).autocomplete({
        source: function( request, response ) {
            $.post("http://mysite.com/v2/ajax/tag_suggestion/ab", {data:request.term}, function(data){
                response($.map(data, function(item) {

                if ($('#tagsboxvals').hasClass(item.name.split(' ').join('_'))){
                return null;

                } else {
                return {
                    label: item.name,
                    value: item.name
                }
                }
                }))
            }, "json");
            },
            ....
});

thanks for the help

Edit: this is what the PHP script generates:

$arr = array(
    array('name'=>'pizza', 'point'=>'1'),
    array('name'=>'blt', 'point'=>'1'));

    header('Cache-Control: no-cache, must-revalidate');
    header('Expires: Mon, 26 Jul 1997 05:00:00 GMT');
    header('Content-type: application/json');
    echo json_encode($arr);

This is a well-formed JSON document.

: , 07 2011 23:58:42 GMT Apache/2.2.3 (CentOS) X-Powered-By PHP/5.1.6 , 26 1997 . 05:00:00 GMT Cache-Control no-cache, -revalidate Pragma - 29 Content-Type/json mysite.com User-Agent Mozilla/5.0 (Macintosh; Intel Mac OS X 10.7; rv: 6.0) Gecko/20100101 Firefox/6.0 /json, text/javascript,/; = 0,01 Accept-Language en-us, en; q = 0.5 Accept-Encoding gzip, deflate Accept-Charset ISO-8859-1, utf-8; q = 0,7, *; q = 0,7 Content-Type/x-www-form-urlencoded; = UTF-8 X-Requested- XMLHttpRequest Referer http://mysite.com/v2/user/register - 8 Cookie city = -; __utma = 100174657.1435105779.1308773648.1314994226.1315368765.113; __utmz = 100174657.1315368765.113.98.utmcsr = mysite.com | utmccn = () | utmcmd = | utmcct =

JSON {name= "", = 1} [ { name= "pizza", point = 1}]

, firefox .

+1
1

, "" json. json, .

100% , - :

{"foo": 1, "bar": "foobar"}

json.

. :

{'foo': 1, 'bar': "foobar"}

:

{foo: 1, bar: "foobar"}

javascript-:

   return {
                label: item.name,
                value: item.name
            }

, .       {                    "label": item.name,                    "value": item.name               }

, ajax- GET-, POST, POST . .

, , . php, json_encode ($ var)

http://php.net/manual/de/function.json-encode.php

:

{"name": "pizza", "point": 1}

php script.

firebug:

var obj = jQuery.parseJSON('[{"name":"pizza","point":1}]');

    for (var i = 0; i < obj.length; i++) {
        var object = obj[i];
        for (property in object) {
        var s = property + "=" + object[property] + "<br>";
            $("#console").after(s); console.log(s)
        }
    }
+2

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