Postgres: how to count individual elements in columns of an array, provided that the condition

Question

I have a table like the following:

ID     array1           array2
7333 | {615593}        | {NULL}
7333 | {2013682}       | {NULL}
7333 | {26573,1508291} | {NULL}
7333 | {1457957}       | {NULL}
7333 | {NULL}          | {1063105}
7333 | {NULL}          | {107978,408431}

I am looking to request all unique elements for array1 and array2 for each edge_id. for instance

ID   array1_distinct    array2_distinct
7333 5                  3

I tried something like the following

SELECT 
  id, 
  array1_count 
FROM (
  SELECT id,
  COUNT(DISTINCT((CASE WHEN array1 is not null THEN (select unnest(array1)b) END)) as array1_count
  FROM mytable
  GROUP BY id
) totals
limit 1

I always get errors such as "more than one row returned by a subquery used as an expression", and "set-valued function called in a context that cannot accept a set" when trying to count elements in arrays when using unsest.

Answer 1

select id, count(distinct a1) as a1, count(distinct a2) as a2
from (
    select id, unnest(array1) as a1, unnest(array2) as a2
    from t
) s
group by id