Change the color of the UIButton BG on the selected, but keep the radius of the corner of the layer?

Question

Im changes the background color UIButtonusing this category method using a 1px image by 1px:

- (void)setBackgroundColor:(UIColor *)backgroundColor forState:(UIControlState)state
{
    UIGraphicsBeginImageContextWithOptions(CGSizeMake(1, 1), NO, 0);
    [backgroundColor setFill];
    CGContextFillRect(UIGraphicsGetCurrentContext(), CGRectMake(0, 0, 1, 1));
    UIImage *backgroundImage = UIGraphicsGetImageFromCurrentImageContext();
    [self setBackgroundImage:backgroundImage forState:state];
    UIGraphicsEndImageContext();
}

However, this overrides my setting .layer.cornerRadius. I need a button with rounded corners, but also one whose background color I can change to the selected one.

How to get around this? The radius of the angle must be dynamic.

Answer 1

So, all I had to do was make sure it was button.layer.masksToBoundson. The problem is resolved; no subclass is required.

Answer 2

UIButton. init. xib, initWithDecoder:

- (id)initWithCoder:(NSCoder *)aDecoder
{
    self = [super initWithCoder:aDecoder];
    if (self) {
        self.layer.cornerRadius = 5.f;
    }

    return self;
}

setHighlighted:. . "" . , . .

- (void)setHighlighted:(BOOL)highlighted
{
    [super setHighlighted:highlighted];

    self.backgroundColor = (highlighted) ? [UIColor redColor] : [UIColor blueColor];
}