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Why can't you create an expression function 1 without curly braces?

So, in most programming languages, if you use a loop or if, you can do this without curly braces if it has only one statement, for example:

if (true)
    //Single statement;

for (int i = 0; i < 10; i++)
    //Single Statement

while (true)
    //Single statement

However, it does not work for functions, for example:

void myFunction()
    //Single Statement

So my question is, why doesn't it work for functions?

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8 answers

C ++ requires it to disambiguate some constructs:

void Foo::bar() const int i = 5;

Now constowned baror i?

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Because language grammar forbids you to do this.

A Java grammar defines a method as follows:

MethodDeclaration:
    MethodHeader MethodBody

Body method like:

MethodBody:
    Block 
    ;

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    { BlockStatementsopt }

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if :

IfThenStatement:
    if ( Expression ) Statement

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: http://docs.oracle.com/javase/specs/jls/se7/html/index.html

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C, ISO/IEC 9899-1999:

6.9.1 Function definitions
Syntax
1     function-definition:
          declaration-specifiers declarator declaration-listopt compound-statement

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compound-statement:
    { block-item-listopt }

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