Spring boot + Spring Security: how to suppress the basic form of authorization

Question

Good afternoon.

I use Spring Security in the context of a downloadable, automatically configured Spring application. My goal is to configure basic auth so that the standard login form of the main browser does not display on 401. From Google, I found out that for this I need to change the default WWW-Authenticate header to something other than Basic xxxxx.

To do this, I declared a filter:

@Bean
@Order(Integer.MAX_VALUE)
public Filter customAuthFilter() {
    return new Filter() {

        @Override
        public void init(FilterConfig fc) throws ServletException {
        }

        @Override
        public void doFilter(ServletRequest sreq, ServletResponse sresp, FilterChain fc) throws IOException, ServletException {
            HttpServletRequest req = (HttpServletRequest) sreq;
            HttpServletResponse resp = (HttpServletResponse) sresp;

            fc.doFilter(req, resp);
            log.info("filter");
            log.info("status " + resp.getStatus());
            if(resp.getStatus() == 401) {
                resp.setHeader("WWW-Authenticate", "Client-driven");
            }
        }

        @Override
        public void destroy() {
        }
    };

, ( doFilter). , , - "WWW-Authenticate". , - , , .

- ?

Answer 1

EntryPoint:

protected void configure(HttpSecurity http) throws Exception {
        http
            .authorizeRequests()
            .antMatchers("/rest/**").authenticated()
            .and().httpBasic().authenticationEntryPoint(new AuthenticationEntryPoint() {
                @Override
                public void commence(HttpServletRequest request, HttpServletResponse response, AuthenticationException authException) throws IOException, ServletException {
                    String requestedBy = request.getHeader("X-Requested-By");
                    log.info("X-Requested-By: " + requestedBy);
                    if(requestedBy == null || requestedBy.isEmpty()) {
                        HttpServletResponse httpResponse = (HttpServletResponse) response;
                        httpResponse.addHeader("WWW-Authenticate", "Basic realm=Cascade Realm");
                        httpResponse.sendError(HttpServletResponse.SC_UNAUTHORIZED, authException.getMessage());
                    } else {
                        HttpServletResponse httpResponse = (HttpServletResponse) response;
                        httpResponse.addHeader("WWW-Authenticate", "Application driven");
                        httpResponse.sendError(HttpServletResponse.SC_UNAUTHORIZED, authException.getMessage());
                    }
                }
            });
}

Answer 2

Spring , , , . . 401 - AuthenticationFailureHandler, , , , , auth .

Answer 3

Just add "X-Requested-With: XMLHttpRequest" to the request header (tested in Spring Security 4.2.2.RELEASE).

For more details, the HttpBasicConfigurer is worth a look up.

Below is my test result using CURL:

hanxideMacBook-Pro:~ hanxi$ curl -u "13980547109:xxx" -v -d "" -H "X-Requested-With: XMLHttpRequest" http://sales.huoxingy.com/api/v1/sales/login
*   Trying 101.37.135.20...
* TCP_NODELAY set
* Connected to sales.huoxingy.com (101.37.135.20) port 80 (#0)
* Server auth using Basic with user '13980547109'
> POST /api/v1/sales/login HTTP/1.1
> Host: sales.huoxingy.com
> Authorization: Basic MTM5ODA1NDcxMDk6MTIzNDU2
> User-Agent: curl/7.54.0
> Accept: */*
> X-Requested-With: XMLHttpRequest
> Content-Length: 0
> Content-Type: application/x-www-form-urlencoded
> 
< HTTP/1.1 200 
< Server: nginx/1.12.1
< Date: Thu, 21 Sep 2017 01:43:13 GMT
< Content-Length: 0
< X-Content-Type-Options: nosniff
< X-XSS-Protection: 1
< Cache-Control: no-cache, no-store, max-age=0, must-revalidate
< Pragma: no-cache
< Expires: 0
< X-Frame-Options: DENY
< X-XSS-Protection: ; mode=block
< x-auth-token: 2f595113-cdba-4394-8ca0-bcd72239bea5
< Set-Cookie: CONTAINERID=efc390abdb189a10c55e0672b07cfe1c7d665be4db9ad40e122475e5cdff605d; path=/