Make sure you only show the Touch ID dialog when the application state is active. If you display it immediately during startup (which means that the application is still technically inactive), then such problems may occur. This is not documented, and I found it the hard way.
For example, to make sure that it starts when the application is active, you can check the current state of the application and either start it immediately, or when we receive an applicationDidBecomeActive notification. The following is an example:
- (void)setup
{
[[NSNotificationCenter defaultCenter] addObserver:self
selector:@selector(applicationDidBecomeActive:)
name:UIApplicationDidBecomeActiveNotification
object:nil];
}
- (void)dealloc
{
[[NSNotificationCenter defaultCenter] removeObserver:self];
}
- (void)viewWillAppear:(BOOL)animated
{
[super viewWillAppear:animated];
if([UIApplication sharedApplication].applicationState == UIApplicationStateActive)
{
[self presentTouchID];
}
else
{
__weak __typeof(self) wSelf = self;
_onActiveBlock = ^{
[wSelf presentTouchID];
};
}
}
-(void)applicationDidBecomeActive:(NSNotification *)notif
{
if(_onActiveBlock)
{
_onActiveBlock();
_onActiveBlock = nil;
}
}
- (void)presentTouchID
{
_context = [[LAContext alloc] init];
_context.localizedFallbackTitle = _fallbackTitle;
[_context evaluatePolicy:LAPolicyDeviceOwnerAuthenticationWithBiometrics
localizedReason:_reason
reply: ^(BOOL success, NSError *authenticationError)
{
}];
}
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