I was waiting for any of the first commentators to answer, but I won’t have them.
c() ..., , . , , c(). . c() ? . , ..., , , ..., .
, , TRUE ( 1) 1:5
as.numeric(TRUE)
c(1:5, TRUE)
c(1:5, rec=TRUE)
, recursive , .
c(1:5)
c(1:5, recursive=TRUE) ## 1:5 not recursive, same result
is.recursive(c(1:5))
(. ?is.recursive).
(x <- as.list(1:5))
is.recursive(x)
c(x, recursive=TRUE)